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Although Checklist for Jira already offers a highly versatile validator, you may sometimes need a custom-scripted validator for more complex validations.

This guide will show you how to build a simple validator, which you can then tailor to your needs.

Steps

1. Retrieve the checklist items from the issue, as seen in the Get a checklist field’s items in an issue example.

2. Keep track of your validation as you loop through the items.
   

   Code Block
   language groovy
   def valid = true; // In this example, we want all items to have a status. // The moment we find an item without a status we want the validation to fail. for (ChecklistItem item : items) { if (!item.hasStatus() && !item.getIsHeader()) { valid = false; // The break instruction stops the loop from continuing. // This isn't mandatory but will help with optimization. break; } }

3. Throw an exception if the validation fails.
   

   Code Block
   language groovy
   if (!valid) { // Jira requires an InvalidInputException throw new InvalidInputException("All items must have statuses"); }

Full example

Here is a full example of a custom validator that verifies that all items have a status.

import com.onresolve.scriptrunner.runner.customisers.WithPlugin;
@WithPlugin("com.okapya.jira.checklist")
import com.okapya.jira.customfields.*;
import com.atlassian.jira.component.ComponentAccessor;
import com.opensymphony.workflow.InvalidInputException;

def customFieldManager = ComponentAccessor.getCustomFieldManager();
// Replace 10000 with your Checklist field's ID
def checklistField = customFieldManager.getCustomFieldObject("customfield_10000");

def ArrayList<ChecklistItem> items = (ArrayList<ChecklistItem>) issue.getCustomFieldValue(checklistField);

def valid = true;
for (ChecklistItem item : items) {
    if (!item.hasStatus() && !item.getIsHeader()) {
        valid = false;
        break;
    }
}

if (!valid) {
    throw new InvalidInputException("At least one item must have a status in the '" + checklistField.getName() + "' Checklist.");
}